-16t^2+60t=10t

Solution for -16t^2+60t=10t equation:

-16t^2+60t=10t

We move all terms to the left:

-16t^2+60t-(10t)=0

We add all the numbers together, and all the variables

-16t^2+50t=0

a = -16; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·(-16)·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*-16}=\frac{-100}{-32}
=3+1/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*-16}=\frac{0}{-32}
=0
$